Your question involves a mix of basic Python syntax, and numpy specific details. In many ways it is the same for lists, but not exactly. arr[:, 0] returns the 1st column of arr (a view), arr[:,0]=10 sets the values of that column to 10. arr[:] returns arr (alist[:] returns a copy of a list). arr[:]=arr2 performs an inplace replacement; changing the values of arr to the values of arr2. The ...
The first element was not selected, which was expected. And if I change 0 to -1, i.e, if I try: arr[len(arr)-1: -1: -1] OR even arr[:-1:-1], I get an empty array. Apparently I get the reversed array view by: arr[::-1] Q: How is this working? If I do not specify the first two arguments how does it infer that it needs to continue till 0? In fact it is just interpreting that it needs to go till ...
i have this code from my previous exam and it's the first time I see this *arr[]. What does that mean? Is it a matrix or an array? And what does it contain? #include
As others have mentioned, *(&arr + 1) triggers undefined behavior because &arr + 1 is a pointer to one-past-the end of an array of type int [7] and that pointer is subsequently dereferenced.
How *(&arr + 1) - arr is working to give the array size
Suppose I have an array of integers called arr. I am trying to understand the distinction between *&arr and *&arr [0]. I read that in C++, arr is essentially a pointer to the first element...