Just printing Integer.MIN_VALUE - 1 and Integer.MAX_VALUE + 1 would have made the point. ... From the Java Language Specification, §15.18.2: If an integer addition overflows, then the result is the low-order bits of the mathematical sum as represented in some sufficiently large two's-complement format.
java Integer.MAX_VALUE, MIN_VALUE overflow Asked 13 years, 7 months ago Modified 3 years, 11 months ago Viewed 32k times
is true. I understand that integer in Java is 32 bit and can't go above 2 31 -1, but I can't understand why adding 1 to its MAX_VALUE results in MIN_VALUE and not in some kind of exception. Not mentioning something like transparent conversion to a bigger type, like Ruby does. Is this behavior specified somewhere? Can I rely on it?
From the Java Language Specification section on integer operations: The built-in integer operators do not indicate overflow or underflow in any way. The results are specified by the language and independent of the JVM version: Integer.MAX_VALUE + 1 == Integer.MIN_VALUE and Integer.MIN_VALUE - 1 == Integer.MAX_VALUE. The same goes for the other integer types. The atomic integer objects ...
To get the max and min values of int in Java, use Integer.MAX_VALUE and Integer.MIN_VALUE
I don't seem to understand how Integer.MAX_VALUE and Integer.MIN_VALUE help in finding the min and max value in an array. I understand how this method (pseudocode below) works when finding the min...
My professor specified that she wants the minimum grade stored in Integer.Max_Value and the maximum grade in Integer.Min_Value. I'm having a rough time comprehending this.
Keeping in mind that after achieving MAX_VALUE in Integer,value goes back to MIN_VALUE and loops again, if a value is <=Integer.MAX_VALUE, then it must be >=Integer.MIN_VALUE, then why does boolean variable d returns false?