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A C++ question, I know int* foo (void) foo will return a pointer to int type how about int &foo (void) what does it return? Thank a lot!
It is a pointer to function that returns int* and accepts int* and pointer to function that returns int* (and accepts undefined number of parameters; see comments).
c - type of int * () (int * , int * () ()) - Stack Overflow
That second memory address, then, is expected to hold an int. Do note that, while you are declaring a pointer to an int, the actual int is not allocated. So it is valid to say int *i = 23, which is saying "I have a variable and I want it to point to memory address 23 which will contain an int."
Difference between the int * i and int** i - Stack Overflow
int* i, int * i, int*i, and int *i are all exactly equivalent. This stems from the C compiler (and it's compatible C like systems) ignoring white space in token stream generated during the process of parsing the source code.
c - difference between int* i and int *i - Stack Overflow
The following code can pass compiling and will print 0 on the console. I saw similar code in STL. Does type int in C++ have a constructor? Is int() a call of some defined function? int main() { ...