Recently learned about this formula to generate consecutive composite numbers $n!+2,n!+3,...,n!+n$ The goal of this question is to find if other methods exist to ...
1 Let's count the number of hands which don't contain any consecutive cards. If all the cards are distinct and there are no consecutive cards, then we have only two possible hands to consider, and they are $\ {1,3,5},\ {2,4,6}$; there are $ {2 \choose 1} {6 \choose 1}^3$ ways to get these hands from our deck of $36$.
Of course you mean " consecutive numbers that are prime", since consecutive prime numbers could be understood in the other way, like $7$ and $11$.
Is there any formula for sum of product of n consecutive integers? [duplicate] Ask Question Asked 1 year, 3 months ago Modified 1 year, 3 months ago
Is there any formula for sum of product of n consecutive integers?
For the language L over an alphabet Σ = {a,b,c}, where there are no two consecutive characters the same, I already managed to draw a finite state automaton. Therefore is is a formal language and there has to be a regular expression for L.
@Baropryl In both of your examples, you construct your consecutive numbers such that the smaller of the two is the even number. You must explicitly consider the case that the smaller of the consecutive numbers is odd.
Confirming a easy proof: the product of two consecutive numbers is ...
Proof on the Greatest Common Divisor of Two Consecutive Integers [duplicate] Ask Question Asked 2 months ago Modified 2 months ago