Essentially casting will not change anything in how it works, it does exactly what it says, allocates memory, and casting does not effect it, you get the same memory, and even if you cast it to something else by mistake (and somehow evade compiler errors) C will access it the same way. Edit: Casting has a certain point.
is there a possibility that casting a double created via Math.round() will still result in a truncated down number No, round() will always round your double to the correct value, and then, it will be cast to an long which will truncate any decimal places. But after rounding, there will not be any fractional parts remaining. Here are the docs from Math.round(double): Returns the closest long to ...
Static cast is also used to cast pointers to related types, for example casting void* to the appropriate type. dynamic_cast Dynamic cast is used to convert pointers and references at run-time, generally for the purpose of casting a pointer or reference up or down an inheritance chain (inheritance hierarchy). dynamic_cast (expression)
Casting from timestamp [us, tz=Etc/UTC] to timestamp [ns] would result in out of bounds timestamp Asked 4 years, 3 months ago Modified 4 years, 3 months ago Viewed 23k times
There are rules about casting pointers, a number of which are in clause 6.3.2.3 of the C 2011 standard. Among other things, pointers to objects may be cast to other pointers to objects and, if converted back, will compare equal to the original.
What are the rules for casting pointers in C? - Stack Overflow
The C-style casts can do virtually all types of casting from normally safe casts done by static_cast<> () and dynamic_cast<> () to potentially dangerous casts like const_cast<> (), where const modifier can be removed so the const variables can be modified and reinterpret_cast<> () that can even reinterpret integer values to pointers.